1 2 X 1 2
1/2 x 1/2 x 1/2 x 1/2 x 1/2 =
1. 1/2 x 1/2 x 1/2 x 1/2 x 1/2 =
1/2 pangkat 5=0.01325
kalo gk salah1/2 x 1/2 x 1/2 x 1/2 x 1/2 = 1/32
2. 1/2 x 1/2 x 1/2 x 1/2 x 1/2=
2×2×2×2×2=36
maaf kalo salah
3. 1/2 x 1/2 x 1/2 x 1/2 ( 1 per 2 x 1 per 2 x ,1 per 2 x 1 per 2 ) nyatakan dalam bentuk bilangan berpangkat
Jawaban:
[tex]\frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = { \frac{1}{2} }^{4}[/tex]
4. 17. Himpunan Penyelesaian dari | 5 − 2x | ≤ 4 adalah ....a. { x | 1 2 ≤ x ≤ 2 1 2 }b. { x | 1 2 ≤ x ≤ 3 1 2 }c. { x | 1 2 ≤ x ≤ 4 1 2 }d. { x | 1 2 ≤ x ≤ 5 1 2 }e. { x | 1 2 ≤ x ≤ 6 1 2
| 5 - 2x | ≤ 4
- 4 ≤ 5 - 2x ≤ 4
- 4 - 5 ≤ - 2x ≤ 4 - 5
- 9 ≤ - 2x ≤ - 1
- 9/2 ≤ - x ≤ - 1/2
9/2 ≥ x ≥ 1/2
1/2 ≤ x ≤ 9/2
½ ≤ x ≤ 4 ½
HP = { x | ½ ≤ x ≤ 4 ½ , x € R }
5. 2∣x−1∣≤∣x+2∣[tex]2∣x−1∣≤∣x+2∣[/tex]2∣x−1∣≤∣x+2∣
Jawaban:
428#@72:$@9264388#@kamu itu sanga tidak pintar kon
6. Mohon bantuannya x^6 - 1 / x^2 - 1 sama dengan...a. x^4-1b. (x^2+x+1)(x^2-x+1)c. (x^2+x+1)(x^2-x-1)d. (x^2+x-1)(x^2-x+1)e. x^4+x^2+1
Jawaban:
e. x^4+x^2+1
Penjelasan dengan langkah-langkah:
semoga benar
7. { ((x^2/3)+(x^1/2))*((x^1/3)-(1/(x^1/3))) } / { ((x^1/2)+1/(x^1/2))*(x-(x^1/3)) } =...
[tex]( x^{ \frac{3}{2} } + x^{ \frac{1}{2} }) ( x^{ \frac{1}{3} } - x^{ -\frac{1}{3} } )[/tex]
[tex]( x^{ \frac{1}{2} } + x^{ -\frac{1}{2} }) ( x - x^{ \frac{1}{3} } )[/tex]
[tex] x^{ \frac{1}{2} } (x + 1) x^{- \frac{1}{3} } ( x^{ \frac{2}{3} } + 1) [/tex]
[tex] x^{ -\frac{1}{2} }(x + 1) x^{ \frac{1}{3}}(x^{ \frac{2}{3} } - 1) [/tex]
dicoret coret
=
[tex] \sqrt[3]{x} [/tex]
8. Kuis ANAK BAYI 1) 1+1+1+1+1+1+1+1+1 (sebanyak 9) 2) 2 x 2 x 2 x 2 x 2 (sebanyak 5)
Jawab:
Penjelasan dengan langkah-langkah:
[tex]1) 1+1+1+1+1+1+1+1+1 = 1\times 9 = 9\\2) 2 \times 2 \times 2 \times 2 \times 2 = 2^5 = 32[/tex]
No1
1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
2 + 1 + 1 + 1 + 1 + 1 + 1 + 1
3 + 1 + 1 + 1 + 1 + 1 + 1
4 + 1 + 1 + 1 + 1 + 1
5 + 1 + 1 + 1 + 1
6 + 1 + 1 + 1
7 + 1 + 1
8 + 1
9
No2
2 × 2 × 2 × 2 × 2
4 × 2 × 2 × 2
8 × 2 × 2
16 × 2
32
9. Tentukan nilai p= 1/3+1/9+1/27+1/81+.... contohnya = ini huruf x ya x=1/2+1/4+1/8+1/16+1/32+... x=1/2 (1+1/2+1/4+1/8+1/16+...) x=1/2(1+ x) x=1/2+1/2 x x-1/2 x =1/2 1/2 x =1/2 x=1/2 : 1/2 =1
p= 1/3 + 1/9 + 1/27 + 1/81 + 1/243 + .......
1/3p=(1/3 + 1/9 + 1/27 + 1/81 + ......)/3
= 1/9 + 1/27 + 1/81 + 1/243 + ....
p-(1/3p) = (1/3 + 1/9 + ...)-(1/9 + 1/27 + ...)
2/3p= 1/3
p= 1/2
10. 1 + 1 =1 x 1 =2 + 2 =2 x 2 =♥️
Jawaban:
1 + 1 = 2
1 × 1 = 1
2 + 2 = 4
2 × 2 = 2
11. Jika cotan 54° = 1/x, maka cosec 9° =… a. x - 1 / x + 1 b. x + 1 / x - 1 c. √2(x^2 + 1) / x - 1 d. √2(x^2 + 1) / x + 1 e. x - 1 / √2(x^2 + 1)
cosec 9° =…
cotan 54° = 1/x
tan 54° = x
cosec 9° = √2(x² + 1) / x - 1
12. Hasil bagi dari pembagian suku banyak (x^6-1):(x²-1) adalah... a. (x^2+x+1) (x^2+x-1) b. (x^2+x+1) (x^2-x+1) c. (x^2+x+1) (x^2-x-1) d. (x^2-x+1) (x^2+x-1) e. (x^2+x-1) (x^2-x-1) beserta caranya ya..
Penjelasan dengan langkah-langkah:
dilampirkan pada gambar...
13. 1. Lim x -> 1 x^2-1 / x^2+3x-2 2. Lim x -> -1 (x+1)(x-4)+2(x-1) / x^2+x-2
1) lim x>1 (x-1)(x+2)/ (x+1)(x+2)
=lim x>1 (x-1)/(x+2)
=(1-1)(1+2)
=0/3
=0
2) lim x-> -1 (x+1)(x-4)+2/(x+2)
=(-1+1)(-1-4)+2/(-1+2)
=(0)(-5)+2/(1)
=0+2/1
=2/1
=2
14. T (x) = R (x^2 +1) = (x^2 + 1) / x^2 , makaT (R(x))= [(R(x))^2 + 1] / (R(x))^2 =[[x/(x-1)]^2 +1] / [x/(x-1)]^2 = (2x^2 -2x + 1) / x^2Jika R(x) = x-1/x+1 dan T(x) = x^2+1/x(1-x), maka(R o T)(x) = ....
Jawaban:
1.garis sejajar
2.garis berpotongan
3.garis berimpit
1.garis sejajar
2.garis berpotongan
3.garis berimpit
15. 2/5 x 1 1/3:1/4 x 2 1/2:2/7 x 1 2/2:2/5 x 3 2/3:1/10 x 2 1/2:4 1/2 x 2 1/3:2 1/5 x 2 1/4:5 1/3 x 1 4/2:1 2/5 x 1 2/4:2 1/15 x 1 2/2:tolongg! pakai cara ya!
[tex]1.) \frac{2}{5} \times 1 \frac{1}{3} = \frac{2}{5} \times \frac{4}{3} = \frac{8}{15} [/tex]
[tex]2.) \frac{1}{10} \times 2 \frac{1}{2} = \frac{1}{10} \times \frac{5}{2} = \frac{5}{20} = \frac{1}{4} [/tex]
[tex]3.) \frac{2}{7} \times 1 \frac{2}{2} = \frac{2}{7} \times \frac{4}{2} = \frac{8}{14} = \frac{4}{7} [/tex]
16. 1) 1 1/2 x 1 = 2) 1/2 x 1 = 3) 1 1/2 x 2 = 4) 1/2 x 2 =
1. 1 1/2 × 1 = 3/2 × 1 = 3/2 = 1 1/2
2. 1/2 x 1 = 1/2
3. 1 1/2 x 2 = 3/2 × 2 = 6/2 = 3
4. 1/2 x 2 = 2/2 = 1
Semoga Membantu
Maaf Klo Salah
17. Jika tan 5⁰ = x, tentukan nilai sin 50⁰ ...A.√2/2 ((x+1)/√(x^2-1))B.√2/2 ((x+1)/√(x^2+1))C.√2/2 ((x-1)/√(x^2+1))D.√2/3 ((x+1)/√(x^2+1))E.√2/3 ((x-1)/√(x^2+1))
Jawab:
B.√2/2 ((x+1)/√(x^2+1))
Penjelasan dengan langkah-langkah:
tan 5= x= x/1 » r = √(x²+1)
sin 5 = x/√(x²+1)
cos 5= 1/√(x²+1)
sin 50= sin (45+5)
= sin 45cos5 + cos 45sin 5
=√2/2 . 1/√(x²+1) + √2/2 . x/√(x²+1)
= √2 / 2√(x²+1) + x√2 / 2√(x²+1)
=( x√2 + √2) / 2√(x²+1)
= √2(x+1) / 2√(x²+1)
= √2/2 [ (x+1)/(x²+1) ]
18. 4. (x - 2 = 1 X-2 =1 x = 1+2. X-2=-1 x= -1+2 x = ..... x = ....
Jawaban:
(x-2=1
X-2=1
x=1+2
X-2=-1
X=-1+2
x=1
Jadi jawabannya adalah 1
semoga membantu
19. Turunan fungsi f(x) = 2x – √x adalah …A2x – 1/2 x^(-(1/2))B2x – 1/2 x^(1/2)C2 – 1/2 x^(1/2)D2x – 1/2 xE2 – 1/2 x^(-(1/2))
Jawaban:
E. 2 – ½ x^(-½)
Penjelasan dengan langkah-langkah:
f(x) = 2x – √x
f(x) = 2x – x^½
turunan pertama
f'(x) = (1)2x^(1-1) – (½)x^(½ - 1)
f'(x) = 2 – ½ x^(-½)
Semoga membantu ya... :)
20. bentuk sederhana dari 2 sin 1/2 x cos 1 1/2 x + 2 sin 2 1/2 x cos 1 1/2 x + 2 sin 1 1/2 x cos 3 1/2 x
Jawab:
Penjelasan dengan langkah-langkah:
trigonometri
rumus"
2 sin x cos x= sin (x+ x) + sin ( x- x)
__
soal
2 sin (¹/₂ x)cos (1¹/₂x) + 2 sin( 2¹/₂ x) cos (1¹/₂ x) + 2 sin (1¹/₂ x) cos (3¹/₂ x)=
. .
i) 2 sin (¹/₂ x)cos (1¹/₂x) = sin (¹/₂ x +1¹/₂x) +sin (¹/₂ x -1¹/₂x)
= sin (2x) + sin (- x)
.
ii) 2 sin( 2¹/₂ x) cos (1¹/₂ x) = sin (2¹/₂ x +1¹/₂x) +sin (2¹/₂ x -1¹/₂x)
= sin (4x) + sin ( x)
.
iii) 2 sin (1¹/₂ x) cos (3¹/₂ x)= sin (1¹/₂ x +3¹/₂x) +sin (1¹/₂ x -3¹/₂x)
= sin (5x) + sin (- 2x)
--
maka
2 sin (¹/₂ x)cos (1¹/₂x) + 2 sin( 2¹/₂ x) cos (1¹/₂ x) + 2 sin (1¹/₂ x) cos (3¹/₂ x)=
= sin 2x - sinx + sin 4x + sin x + sin 5x - sin 2x
= sin 4x + sin 5x
Video Update
Reviewed by Franco
on
May 22, 2023
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